Ответ:
2sin2x=−
3
sin2x=−
/2
2x=(−1)
n+1
∗π/3+πn,n\inZ
x=(−1)
∗π/6+πn/2,n∈Z
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Ответ:
2sin2x=−
3
sin2x=−
3
/2
2x=(−1)
n+1
∗π/3+πn,n\inZ
x=(−1)
n+1
∗π/6+πn/2,n∈Z