Реши систему уравнений методом подстановки:
{2−5(0,2y−2k)=3(3k+2)+2y4(k−2y)−(2k+y)=2−2(2k+y)
{2−5(0,2y−2k)=3(3k+2)+2y4(k−2y)−(2k+y)=2−2(2k+y)
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