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gamelove4002
@gamelove4002
August 2021
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Определите константу химического равновесия
3H2+N2-- 2NH3 , [H2]=0.02 моль/л , [N2]=0.01 моль/л, {NH3]=0.03 моль/л.
1
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Sidrial
Sidrial
Ответ:
K = 11250
Объяснение:
K =
Ответ:
K = 11250
Объяснение:
K = \frac{[NH3]^{2} }{[H2]^{3}[N2] } = \frac{0,03^{2} }{0,02^{3}*0,01 } = 0,0009/0.00000008 = 11250
[H2]
3
[N2]
[NH3]
2
=
0,02
3
∗0,01
0,03
2
=0,0009/0.00000008=11250
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