Объяснение:
[tex]\frac{0.04m^2-1}{0.04m^2-0.4m+1}=[/tex]
[tex]\frac{(0.2m)^2-1^2}{(0.2m)^2-2*0.2m*1+1^2}=[/tex]
[tex]\frac{(0.2m-1)(0.2m+1)}{(0.2m-1)^2}=[/tex]
[tex]\frac{0.2m+1}{0.2m-1}=\frac{(0.2m+1)*5}{(0.2m-1)*5}=\frac{m+5}{m-5}[/tex]
Ответ:
(0.2m+1)/(0.2m-1)
a²-2ac+c²=(a-c)²
a²-c²=(a-c)(a+c)
0.04m²-1=(0.2m-1)(0.2m+1)
0.04m²- 0.4m+1=(0.2m-1)²
(0.04m²-1)/(0.04m²- 0.4m+1)=(0.2m-1)(0.2m+1)/(0.2m-1)²=(0.2m+1)/(0.2m-1)
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Answers & Comments
Объяснение:
[tex]\frac{0.04m^2-1}{0.04m^2-0.4m+1}=[/tex]
[tex]\frac{(0.2m)^2-1^2}{(0.2m)^2-2*0.2m*1+1^2}=[/tex]
[tex]\frac{(0.2m-1)(0.2m+1)}{(0.2m-1)^2}=[/tex]
[tex]\frac{0.2m+1}{0.2m-1}=\frac{(0.2m+1)*5}{(0.2m-1)*5}=\frac{m+5}{m-5}[/tex]
Ответ:
(0.2m+1)/(0.2m-1)
Объяснение:
a²-2ac+c²=(a-c)²
a²-c²=(a-c)(a+c)
0.04m²-1=(0.2m-1)(0.2m+1)
0.04m²- 0.4m+1=(0.2m-1)²
(0.04m²-1)/(0.04m²- 0.4m+1)=(0.2m-1)(0.2m+1)/(0.2m-1)²=(0.2m+1)/(0.2m-1)