Ответ:
1)sin300°=sin(360°-60°)=(-π/3)=-√3/2
2)10*1/2+8*1/2=5+4=9
3)sin(125°+55°)=sin(180°)=0
4)2sin105°cos105°=sin2a=sin2*105°=sin210°=-1/2
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Ответ:
1)sin300°=sin(360°-60°)=(-π/3)=-√3/2
2)10*1/2+8*1/2=5+4=9
3)sin(125°+55°)=sin(180°)=0
4)2sin105°cos105°=sin2a=sin2*105°=sin210°=-1/2