0.19. Решите уравнение:
1) (х+1)(х+2) =(x-3)(х+4);
2) (3x-1)(2x+7) - (х+1)(6х-5) = 16;
3) 24 - (3y+1)(4y – 5) = (11 - 6у)(2y-1)+6;
4) (6y + 2)(5-y) =47 - (2y – 3)(3y -1).
1) (х+1)(х+2) =(x-3)(х+4);
2) (3x-1)(2x+7) - (х+1)(6х-5) = 16;
3) 24 - (3y+1)(4y – 5) = (11 - 6у)(2y-1)+6;
4) (6y + 2)(5-y) =47 - (2y – 3)(3y -1).
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Пошаговое объяснение:
х^2+2х+х+2=х^2+4х-3х-12
х^2+3х+2-х^2-4х+3х+12=0
2х+14=0
2х=-14
х=-14÷2
х=-7
6х^2+21х-2х-7-6х^2+5х-6х+5-16=0
18х-2-16=0
18х-18=0
х=18÷18
×=1
24-12у^2+15у-4у+5-22у+11+12у^2-6у-6=0
-17у+34=0
-17у=-34
у=34÷17
у=2
30у-6у^2+10-2у=47-6у^2+2у+9у-3
28у-6у^2+10-47+6у^2-2у-9у+3=0
17у=34
у=34÷17
у=2