0,2a·(5b²c)+a²b·(bc)²+ab²c = ab²c + a²b·b²c² + ab²c = 2ab²c + a²b³c²
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0,2a·(5b²c)+a²b·(bc)²+ab²c = ab²c + a²b·b²c² + ab²c = 2ab²c + a²b³c²