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[tex]1)\ \ \displaystyle 1\frac{1}{2}\cdot 3\frac{1}{3}-4\frac{4}{9}:4=\frac{3}{2}\cdot \frac{10}{3}-\frac{40}{9}\cdot \frac{1}{4}=5-\frac{10}{9}=\frac{5\cdot 9-10}{9}=\frac{35}{9}=\bf 3\frac{8}{9}[/tex]

[tex]\displaystyle 2)\ \ 3\frac{2}{7}\cdot 1\frac{1}{3}+3\frac{2}{7}\cdot 1\frac{2}{3}=3\frac{2}{7}\cdot \Big( 1\frac{1}{3}+1\frac{2}{3}\Big)=3\frac{2}{7}\cdot3=\frac{23}{7}\cdot 3=\frac{69}{7}=\bf 9\frac{6}{7}[/tex]