Verified answer

Ответ:

60г/моль

Объяснение:

2CₙH₂ₙ₊₁COOH + Ca = (CₙH₂ₙ₊₁COO)₂Ca + H₂

Mr(CₙH₂ₙ₊₁COOH) = 12n+2n+1+12+16*2+1 = 14n+46

{28n+92 г (CₙH₂ₙ₊₁COOH) - 22,4л (H₂)

6 г (CₙH₂ₙ₊₁COOH) - 1,12л (H₂)

6*22,4 = 1,12*(28n+92)

134,4 = 31,36n+103,04

31,36n = 134,4-103,04

31,36n = 31,36

n = 1

CH3COOH

Mr(CH3COOH) = 60г/моль