[tex]1) {x}^{3} - 16x = 0 \\ x( {x}^{2} - 16) = 0 \\ x = 0 \\ {x}^{2} - 16 = 0 [/tex]

Ответ: х=0, х=-4, х=4

[tex]2) {x}^{3} + {6x}^{2} - x - 6 = 0 \\ {x}^{2} (x + 6) - (x + 6) = 0 \\ (x + 6)( {x}^{2} - 1) = 0 \\ x + 6 = 0 \\ {x}^{2} - 1 = 0[/tex]

Ответ: х=-6, х=1, х=-1