[tex]\displaystyle\bf\\\left \{ {{\dfrac{2x+3y}{2}+\dfrac{3x-2y}{7} =\dfrac{43}{14} } \atop {\dfrac{3x+2y}{2} -\dfrac{5x-y}{5} =\dfrac{3}{10} }} \right. \\\\\\\left \{ {{\dfrac{2x+3y}{2}\cdot 14+\dfrac{3x-2y}{7} \cdot 14 =\dfrac{43}{14}\cdot 14 } \atop {\dfrac{3x+2y}{2} \cdot 10-\dfrac{5x-y}{5} \cdot 10=\dfrac{3}{10}\cdot 10 }} \right. \\\\\\\left \{ {{(2x+3y)\cdot 7+(3x-2y)\cdot 2=43} \atop {(3x+2y)\cdot 5-(5x-y)\cdot 2=3}} \right.[/tex]
[tex]\displaystyle\bf\\\left \{ {{14x+21y+6x-4y=43} \atop {15x+10y-10x+2y=3}} \right. \\\\\\\left \{ {{20x+17y=43} \atop {5x+12y=3} \ |\cdot(-4)} \right. \\\\\\+\left \{ {{20x+17y=43} \atop {-20x-48y=-12}} \right. \\------------\\-31y=31\\\\y=31:(-31)=-1\\\\5x=3-12y=3-12\cdot (-1)=3+12=15\\\\x=15:5=3\\\\Otvet \ : \ \Big(3 \ ; \ -1\Big)[/tex]
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[tex]\displaystyle\bf\\\left \{ {{\dfrac{2x+3y}{2}+\dfrac{3x-2y}{7} =\dfrac{43}{14} } \atop {\dfrac{3x+2y}{2} -\dfrac{5x-y}{5} =\dfrac{3}{10} }} \right. \\\\\\\left \{ {{\dfrac{2x+3y}{2}\cdot 14+\dfrac{3x-2y}{7} \cdot 14 =\dfrac{43}{14}\cdot 14 } \atop {\dfrac{3x+2y}{2} \cdot 10-\dfrac{5x-y}{5} \cdot 10=\dfrac{3}{10}\cdot 10 }} \right. \\\\\\\left \{ {{(2x+3y)\cdot 7+(3x-2y)\cdot 2=43} \atop {(3x+2y)\cdot 5-(5x-y)\cdot 2=3}} \right.[/tex]
[tex]\displaystyle\bf\\\left \{ {{14x+21y+6x-4y=43} \atop {15x+10y-10x+2y=3}} \right. \\\\\\\left \{ {{20x+17y=43} \atop {5x+12y=3} \ |\cdot(-4)} \right. \\\\\\+\left \{ {{20x+17y=43} \atop {-20x-48y=-12}} \right. \\------------\\-31y=31\\\\y=31:(-31)=-1\\\\5x=3-12y=3-12\cdot (-1)=3+12=15\\\\x=15:5=3\\\\Otvet \ : \ \Big(3 \ ; \ -1\Big)[/tex]