0.5у×(2у-1)-(0.5-2у)+1=0...

June 2022 1 8 Report

0.5у×(2у-1)-(0.5-2у)+1=0

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Aishat99 $0.5y(2y-1)-(0.5-2y)+1=0$
$y^{2} -0.5y-0.5+2y+1=0$
$y^{2} +1.5y+0.5=0$
$2y^{2} +3y+1=0$
$D=9-8=1$
$y1= \frac{-3+1}{4} =-0.5$

0 votes Thanks 1

Aishat99 y2=(-3-1)/4=-1

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