0,5y^3-0,5y(y+1)(y-3)=7. Created by Алинулька11. algebra-ru

0,5y^3-0,5y(y+1)(y-3)=7...

July 2022 1 9 Report

0,5y^3-0,5y(y+1)(y-3)=7

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rubilovalex 0,5y^3-0,5y*(y^2-2y-3)=7; 0,5y^3-0,5y^3+y^2+1,5y-7=0; y^2+1,5y-7=0; 2y^2+3y-14=0; D=3^2-4*2*(-14)=9+112=121; y1=(-3-11)/4, y2=(-3+11)/4. y1= -3,5; y2=2. Ответ: y1= -3,5; y2=2.

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