Ответ:
[tex]2a \times ( - a + 2 {a}^{2} ) = - 2 {a}^{2} + 4 {a}^{3} \\ 8ab \times (5c + 2a) = 40abc + 16 {a}^{2} b \\ - 4xy \times (2x - y) = - 8 {x}^{2} + 4x {y}^{2} \\ 5 {x}^{3} \times (3 {x}^{3} - 2x + 1) = 15 {x}^{6} - 10 {x}^{4} + 5 {x}^{3} \\ - 8 {m}^{3} n \times (m {n}^{2} - mn - {n}^{2} ) = - 8 {m}^{4} {n}^{3} + 8 {m}^{4} {n}^{2} + 8 {m}^{3} {n}^{ 3} \\ \\ - 3 {x}^{3} y \times (2 {x}^{2} y + 4 {y}^{3} x) = - 6 {x}^{5} {y}^{2} - 12 {x}^{4} {y}^{4} [/tex]
[tex]8a + 8 = 8 \times (a + 1) \\ 15x - 25y = 5 \times (3x - 5y) \\ - bx - ax = - x \times (b + a) \\ 9ax - 9bx = 9x \times (a - b) \\ 3ay - 6y = 3y \times (a- 2) \\ - 7ab + 14b = 7b \times ( - a + 2)[/tex]
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Ответ:
[tex]2a \times ( - a + 2 {a}^{2} ) = - 2 {a}^{2} + 4 {a}^{3} \\ 8ab \times (5c + 2a) = 40abc + 16 {a}^{2} b \\ - 4xy \times (2x - y) = - 8 {x}^{2} + 4x {y}^{2} \\ 5 {x}^{3} \times (3 {x}^{3} - 2x + 1) = 15 {x}^{6} - 10 {x}^{4} + 5 {x}^{3} \\ - 8 {m}^{3} n \times (m {n}^{2} - mn - {n}^{2} ) = - 8 {m}^{4} {n}^{3} + 8 {m}^{4} {n}^{2} + 8 {m}^{3} {n}^{ 3} \\ \\ - 3 {x}^{3} y \times (2 {x}^{2} y + 4 {y}^{3} x) = - 6 {x}^{5} {y}^{2} - 12 {x}^{4} {y}^{4} [/tex]
[tex]8a + 8 = 8 \times (a + 1) \\ 15x - 25y = 5 \times (3x - 5y) \\ - bx - ax = - x \times (b + a) \\ 9ax - 9bx = 9x \times (a - b) \\ 3ay - 6y = 3y \times (a- 2) \\ - 7ab + 14b = 7b \times ( - a + 2)[/tex]