Объяснение:
A(6;0) B(0;4)
[tex]\displaystyle\\\boxed {\frac{x-x_A}{x_B-x_A}=\frac{y-y_A}{y_B-y_A} }[/tex]
[tex]\displaystyle\\\frac{x-6}{0-6} =\frac{y-0}{4-0} \\\\\\\frac{x-6}{-6} =\frac{y}{4} \ |*4\\\\\\-\frac{4}{6}*(x-6)=y\\\\y=-\frac{2}{3}x+4\ |*3 \\\\3y=-2x+12.\\[/tex]
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Объяснение:
A(6;0) B(0;4)
[tex]\displaystyle\\\boxed {\frac{x-x_A}{x_B-x_A}=\frac{y-y_A}{y_B-y_A} }[/tex]
[tex]\displaystyle\\\frac{x-6}{0-6} =\frac{y-0}{4-0} \\\\\\\frac{x-6}{-6} =\frac{y}{4} \ |*4\\\\\\-\frac{4}{6}*(x-6)=y\\\\y=-\frac{2}{3}x+4\ |*3 \\\\3y=-2x+12.\\[/tex]