[tex]f(x) = 10x \\ f(0.1) = 10 \times 0.1 = 1[/tex]
[tex]f(x) = 2 - 5x \\ f(0.2) = 2 - 5 \times 0.2 = 2 - 1 = 1[/tex]
[tex]f(x) = - 1.5x + 3 \\ f(10) = - 1.5 \times 10 + 3 = \\ - 15 + 3 = - 12[/tex]
[tex]f(x) = \frac{3}{x} \\ f(0.3) = \frac{3}{0.3} = \frac{30}{3} = 10[/tex]
[tex]f(x) = \frac{4x - 6}{2} \\ f( - 2) = \frac{4 \times ( - 2) - 6}{2} = \\ \frac{ - 8 - 6}{2} = - \frac{14}{2} = - 7[/tex]
[tex]f(x) = \frac{2}{ {x}^{2} + 1} \\ f( - 1) = \frac{2}{( - 1) {}^{2} + 1} = \frac{2}{1 + 1} = \frac{2}{2} = 1[/tex]
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Answers & Comments
а)
[tex]f(x) = 10x \\ f(0.1) = 10 \times 0.1 = 1[/tex]
б)
[tex]f(x) = 2 - 5x \\ f(0.2) = 2 - 5 \times 0.2 = 2 - 1 = 1[/tex]
в)
[tex]f(x) = - 1.5x + 3 \\ f(10) = - 1.5 \times 10 + 3 = \\ - 15 + 3 = - 12[/tex]
г)
[tex]f(x) = \frac{3}{x} \\ f(0.3) = \frac{3}{0.3} = \frac{30}{3} = 10[/tex]
д)
[tex]f(x) = \frac{4x - 6}{2} \\ f( - 2) = \frac{4 \times ( - 2) - 6}{2} = \\ \frac{ - 8 - 6}{2} = - \frac{14}{2} = - 7[/tex]
е)
[tex]f(x) = \frac{2}{ {x}^{2} + 1} \\ f( - 1) = \frac{2}{( - 1) {}^{2} + 1} = \frac{2}{1 + 1} = \frac{2}{2} = 1[/tex]