[tex]\displaystyle\bf\\\Big(x-8\Big)\cdot\Big(x-3\Big)=x\cdot x-x\cdot3-8\cdot x-8\cdot(-3)=x^{2} -3x-8x+24=\\\\\\=x^{2} \boxed{-} \ \boxed{11} \ x \ \boxed{+} \ \boxed{24}[/tex]