Ответ:
Вот решение
Объяснение:
на листочке
[tex] {(2 + t)}^{2} = 4 \\ 4 + 4t + {t}^{2} = 4 \\ t(t + 4) = 0 \\ \\ t1 = 0 \\ t2 = - 4[/tex]
[tex] {(x - 0.2)}^{2} = - 0.09 \\ {x}^{2} - 0.4x + 0.04 = - 0.09 \\ {x}^{2} -0.4x + 0.13 = 0 \\ d < 0[/tex]
[tex] {(x + 4)}^{2} = 5 \\ {x}^{2} + 8x + 16 = 5 \\ {x}^{2} + 8x + 11 = 0 \\ d = 20 \\ x1 = \frac{ - 8 - 2 \sqrt{5} }{2} = - 4 - \sqrt{5} \\ x2 = - 4 + \sqrt{5} [/tex]
[tex] {(7 - y)}^{2} = 2 \\ 49 - 14y + {y}^{2} = 2 \\ {y}^{2} - 14y + 47 = 0 \\ d = 8 \\ x1 = 7 + \sqrt{2} \\ x 2 = 7 - \sqrt{2} [/tex]
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
Ответ:
Вот решение
Объяснение:
на листочке
Ответ:
[tex] {(2 + t)}^{2} = 4 \\ 4 + 4t + {t}^{2} = 4 \\ t(t + 4) = 0 \\ \\ t1 = 0 \\ t2 = - 4[/tex]
[tex] {(x - 0.2)}^{2} = - 0.09 \\ {x}^{2} - 0.4x + 0.04 = - 0.09 \\ {x}^{2} -0.4x + 0.13 = 0 \\ d < 0[/tex]
[tex] {(x + 4)}^{2} = 5 \\ {x}^{2} + 8x + 16 = 5 \\ {x}^{2} + 8x + 11 = 0 \\ d = 20 \\ x1 = \frac{ - 8 - 2 \sqrt{5} }{2} = - 4 - \sqrt{5} \\ x2 = - 4 + \sqrt{5} [/tex]
[tex] {(7 - y)}^{2} = 2 \\ 49 - 14y + {y}^{2} = 2 \\ {y}^{2} - 14y + 47 = 0 \\ d = 8 \\ x1 = 7 + \sqrt{2} \\ x 2 = 7 - \sqrt{2} [/tex]