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Annamontellior
@Annamontellior
August 2021
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1) 0,6x2y· (-0,5x5y7)
2) 0,6x4 ·(-10x4) 3
3) (2a7x12) 4 · ax
4) (3a2 - 11a + 4) – (6a2 - 2a - 3)
5) 3a3 ·(2a2 - 4)
6) (x + 1) (x2 - 3x - 4)
7) (x + 5) (2 x2 - 2) -10x2
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sumaya13q
Ответ:
Объяснение:
0,6x2y * (-0,5x5y7) = 1,2xy * (-17,5xy) = 21x^2 y^2
0,6x4 * (-10x4)3 = 2,4x * (-40x) 3 = -288 x^2
(2a7x12)4 * ax = 168ax * 4ax = 672a^2 x^2
(3a2 - 11a + 4) - (6a2 - 2a - 3) = (6a - 11a + 4) - (12a - 2a - 3) = (-5a + 4) - (10a - 3) = -5a + 4 - 10a + 3 = -15a + 7
3a3 * (2a2 - 4) = 9a * (4a - 4) - 36a^2 - 36s
(x + 1) (x2 - 3x - 4) = (x + 1) (-x - 4) = -(x+1) (x+4) = -(x^2 + 5x + 4) = -x^2 - 5x - 4
(x+5) (2x2 - 2) - 10x2 = (x+5) (4x-2) - 20x = 4x^2 - 18x - 10 - 20x = 4x^2 - 38x - 10
4 votes
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Annamontellior
Спасибо огромное!
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