1. Піднесіть до квадрата : 1. (3+с)² =
2.(9х- 2у)=
2. Розкласти на множники: 1. 4х²+12ха+9а²=
2. 121а⁴- 64b^6=
2.(9х- 2у)=
2. Розкласти на множники: 1. 4х²+12ха+9а²=
2. 121а⁴- 64b^6=
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Answers & Comments
9+6с+с^2
с^2+6с+9
(9х-2у)^2
(9х)^2-2 * 9х * 2у+(2у)^2
81х^2 - 36ху + 4у^2
4х^2+ 12ха + 9а^2
2^2 * х^2+2 * 2х * 3а+3^2 * а^2
(2х)^2 +2 * 2х * 3а+(3а)^2
(2х+3а)^2
121а^4-64b^6
11^2 * a^2*2 -8^2 * b^2*3
11^2 * (a^2)^2 - 8^2 * (b^3)^2
(11 * a^2)^2 - (8 * b^3)^2
(11 * a^2 - 8 * b^3) * (11 * a^2 + 8 * b^3)