[tex] {x}^{2} - 1.44 = 0 \\ (x - 1.2)(x + 1.2) = 0 \\ x_{1} =1.2 \\ x _{2} = - 1.2[/tex]
[tex](b - 3) {}^{2} + 5 {b}^{2} = {b}^{2} - 6b + 9 + 5 {b}^{2} = \\ 6 {b}^{2} - 6b + 9 = 3(3 {b}^{2} - 2b + 3)[/tex]
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[tex] {x}^{2} - 1.44 = 0 \\ (x - 1.2)(x + 1.2) = 0 \\ x_{1} =1.2 \\ x _{2} = - 1.2[/tex]
[tex](b - 3) {}^{2} + 5 {b}^{2} = {b}^{2} - 6b + 9 + 5 {b}^{2} = \\ 6 {b}^{2} - 6b + 9 = 3(3 {b}^{2} - 2b + 3)[/tex]