Verified answer

[tex] \frac{ {2}^{8} {( {2}^{3} )}^{2} }{ {2}^{12} } = \frac{ {2}^{8} \times {2}^{6} }{ {2}^{12} } = \frac{ {2}^{14} }{ {2}^{12} } = {2}^{2} = 4[/tex]