1)
-12х - 5 = -8х +16
-12х + 8х = 16 + 5
-4х = 21
х = -21 : 4
х = -5,25
2)
3,5 · (4х - 6) - 3 · (4,5х + 0,5) = -2,5
14х - 21 - 13,5х -1,5 = -2,5
14х - 13,5х = -2,5 + 21 + 1,5
0,5х = 20
х = 20 : 0,5
х = 40
3)
-2 (х + 6) + 15 = - (2х + 4) + 13
-2х - 12 + 15 = -2х - 4 +13
-12 + 15 = -4 + 13
3 = 9, утверждение ложно, поэтому решение ∅
4)
[tex]\frac{x+3,5}{4}= \frac{2x-5,25}{7}[/tex]
[tex]\frac{x+\frac{7}{2} }{4}=\frac{2x-\frac{21}{4} }{7}[/tex]
[tex]\frac{\frac{2x+7}{2} }{4}=\frac{\frac{8x-21}{4} }{7}[/tex]
[tex]\frac{2x+7}{8}=\frac{8x-21}{28}[/tex]
28 (2x + 7) = 8 (8x - 21)
56x + 196 = 64x - 168
56x - 64x = -168 - 196
-8x = -364
x = 364 : 8
х = 45,5
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Answers & Comments
1)
-12х - 5 = -8х +16
-12х + 8х = 16 + 5
-4х = 21
х = -21 : 4
х = -5,25
2)
3,5 · (4х - 6) - 3 · (4,5х + 0,5) = -2,5
14х - 21 - 13,5х -1,5 = -2,5
14х - 13,5х = -2,5 + 21 + 1,5
0,5х = 20
х = 20 : 0,5
х = 40
3)
-2 (х + 6) + 15 = - (2х + 4) + 13
-2х - 12 + 15 = -2х - 4 +13
-12 + 15 = -4 + 13
3 = 9, утверждение ложно, поэтому решение ∅
4)
[tex]\frac{x+3,5}{4}= \frac{2x-5,25}{7}[/tex]
[tex]\frac{x+\frac{7}{2} }{4}=\frac{2x-\frac{21}{4} }{7}[/tex]
[tex]\frac{\frac{2x+7}{2} }{4}=\frac{\frac{8x-21}{4} }{7}[/tex]
[tex]\frac{2x+7}{8}=\frac{8x-21}{28}[/tex]
28 (2x + 7) = 8 (8x - 21)
56x + 196 = 64x - 168
56x - 64x = -168 - 196
-8x = -364
x = 364 : 8
х = 45,5