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a7078598181
@a7078598181
February 2023
1
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СРОООЧНО!!!!
1-2 расписать все в тетраде.
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wlxnikaj
1.) f(x)= 3x (2) - x (2) -2;
f (x = 2x (2) -2
a= 2, b= 0
x= 0_2x2 (дробь,0-числитель,2*2 знаменатель)
x=0
f (x)= 3x (2)-x2-2,x=0
f(0)= -2
(0, -2)
2.) f (x) = sin2x + cos2x -2
f’(x) d_dx (sin(2x) + cos(2x)-2)
f’(x)=d_dx(sin(2x)) + (cos(2x))-d_dx(2)
f’(x)=cos(2x) x2-sin(2x)x2-0
f’(x)= 2cos(2x)-2sin(2x)
0 votes
Thanks 0
a7078598181
там не 3 а 2 надо было
wlxnikaj
знаю,ошиблась
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Answers & Comments
f (x = 2x (2) -2
a= 2, b= 0
x= 0_2x2 (дробь,0-числитель,2*2 знаменатель)
x=0
f (x)= 3x (2)-x2-2,x=0
f(0)= -2
(0, -2)
2.) f (x) = sin2x + cos2x -2
f’(x) d_dx (sin(2x) + cos(2x)-2)
f’(x)=d_dx(sin(2x)) + (cos(2x))-d_dx(2)
f’(x)=cos(2x) x2-sin(2x)x2-0
f’(x)= 2cos(2x)-2sin(2x)