Verified answer

[tex]\displaystyle\bf\\1)\\\\(x-7)(x+5) > 0[/tex]

[tex]\displaystyle\bf\\ \ + + + + + (-5) - - - - - (7) + + + + + \\[/tex]

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[tex]\displaystyle\bf\\Otvet: \ x\in\Big(-\infty \ ; \ -5\Big) \ \cup \Big (7 \ ; \ +\infty\Big)\\\\\\2)\\\\y=x^{2} -8x+7\\\\x^{2} -8x+7\geq 0\\\\Otvet: \ x\in\Big(-\infty \ ; \ 1\Big] \ \cup \ \Big[7 \ ; \ +\infty\Big)[/tex]