Ответ:
sin(α−β)+2sinβcosα=sinαcosβ−sinβcosα+2sinβcosα=
=sinαcosβ+sinβcosα=sin(α+β)=sinπ=0
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Ответ:
sin(α−β)+2sinβcosα=sinαcosβ−sinβcosα+2sinβcosα=
=sinαcosβ+sinβcosα=sin(α+β)=sinπ=0