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nza546gh
@nza546gh
July 2023
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1)√а¹¹;
2)√2х¹⁴,якщо х < 0
Даю 40 Балога
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Vlayd
[tex]a {}^{5} \sqrt{a} [/tex]
[tex] \sqrt{2x {}^{7} } [/tex]
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