1) (2а + 1)2 = 4а2 + 4а + 1
2) с2 – b2-7c+7b=(c-b)(c+b+7)
3) 729с3– 125b3 = (9с – 5b)(81с2+45cb+2 5b2)
4) (1,2у2 – 0,5х3)2 = 14,4у4- 1, 2х3у2 +0,25 х6
5) (m+3 )2 –(m-2)(m+2)= 6m+5
6) (3х + 2у)(2у – 3х) = 4у2 – 9х2
7) (5а + 3в)2 = 25а2 + 9в2
8) (4р – 5с)(4р + 5с) = 8р2 – 10с2
2) с2 – b2-7c+7b=(c-b)(c+b+7)
3) 729с3– 125b3 = (9с – 5b)(81с2+45cb+2 5b2)
4) (1,2у2 – 0,5х3)2 = 14,4у4- 1, 2х3у2 +0,25 х6
5) (m+3 )2 –(m-2)(m+2)= 6m+5
6) (3х + 2у)(2у – 3х) = 4у2 – 9х2
7) (5а + 3в)2 = 25а2 + 9в2
8) (4р – 5с)(4р + 5с) = 8р2 – 10с2
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Ответ:
1)4а+2=4a²+4a+1
2-1=4a²+4a-4a
1=4a²
a²=0,25
a=0,5