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legionff
@legionff
July 2022
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найдите значение выражения m-6n^2/2n-1 + 3n-2n/1-2n при m=12, n=-3
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irinaorlova2
М -6п²\2п-1+3п -2п\1-2п =-(м-6п²)\1-2п +3п(1-2п)-2п\1-2п=-м+6п²+3п-6п²-2п\
1-2п=-м+п\1-2п
м=12 п=-3
-12+(-3)\1-2*(-3)=-15\6=-5\2=-2 1\2
у меня так получается
2 votes
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Answers & Comments
1-2п=-м+п\1-2п
м=12 п=-3
-12+(-3)\1-2*(-3)=-15\6=-5\2=-2 1\2
у меня так получается