Ответ:
Применяем свойства степеней :
[tex]\bf (ab)^{n}=a^{n}b^{n}\ \ ,\ \ (a^{n})^{k}=a^{n\cdot k}\ \ ,\ \ \ \dfrac{a^{n}}{a^{k}}=a^{n-k}[/tex] .
[tex]\displaystyle \frac{(x^5y^6)^4}{x^{20}y^{22}}=\frac{x^{20}y^{24}}{x^{20}y^{22}}=y^2\\\\\\\frac{(x^8y^4)^3}{x^{23}y^{12}}=\frac{x^{24}y^{12}}{x^{23}y^{12}}=x\\\\\\ y^{20}\cdot \Big(\frac{z^2}{y^5}\Big)^4=\frac{y^{20}z^8}{y^{20}}=z^8[/tex]
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Ответ:
Применяем свойства степеней :
[tex]\bf (ab)^{n}=a^{n}b^{n}\ \ ,\ \ (a^{n})^{k}=a^{n\cdot k}\ \ ,\ \ \ \dfrac{a^{n}}{a^{k}}=a^{n-k}[/tex] .
[tex]\displaystyle \frac{(x^5y^6)^4}{x^{20}y^{22}}=\frac{x^{20}y^{24}}{x^{20}y^{22}}=y^2\\\\\\\frac{(x^8y^4)^3}{x^{23}y^{12}}=\frac{x^{24}y^{12}}{x^{23}y^{12}}=x\\\\\\ y^{20}\cdot \Big(\frac{z^2}{y^5}\Big)^4=\frac{y^{20}z^8}{y^{20}}=z^8[/tex]