Verified answer

[tex]\displaystyle\bf\\\left \{ {{3(2x-2)+7 > 4(x-1)-13} \atop {5(1-x)+3\geq 2(x+1)-2x}} \right.\\\\\\\left \{ {{6x-6+7 > 4x-4-13} \atop {5-5x+3\geq 2x+2-2x}} \right.\\\\\\\left \{ {{6x+1 > 4x-17} \atop {-5x+8\geq 2}} \right. \\\\\\\left \{ {{6x-4x > -17-1} \atop {-5x\geq 2-8}} \right. \\\\\\\left \{ {{2x > -18} \atop {-5x\geq -6}} \right. \\\\\\\left \{ {{x > -9} \atop {x\leq 1,2}} \right. \\\\\\x\in\Big(-9 \ ; \ 1,2\Big]\\\\\\Otvet \ : \ 1[/tex]