1) 3cosx-sin2x=0 2) cotx-cos (pi-x)= 0. Created by MK20. algebra-ru

1) 3cosx-sin2x=0 2) cotx-cos (pi-x)= 0...

July 2022 1 18 Report

1) 3cosx-sin2x=0

2) cotx-cos (pi-x)= 0

Answers & Comments

Bestperson 1)3cosx-sin2x=0
3cosx-2sinxcosx=0
cosx(3-2sinx)=0
cosx=0
x=pi/2+pi*n,n∈z
3-2sinx=0
-2sinx=-3
sinx=3/2
-1≤sinx≤1
3/2>1
sinx≠3/2
ответ:x=pi/2+pi*n

2 votes Thanks 1

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