1) 3y-25-(11-5y)=17; 2) 5y-3-(3+4y)=8; 3) 23-(12x - 23) = 8x + 20 4) 23x - 45= 13x -(5x-6) срочно надо. Created by leyla120209. matematika-ru

Ответ:Пошаговое объяснение:

1) 3y-25-(11-5y)=17; 2) 5y-3-(3+4y)=8; 3) 23-(12x - 23) = 8x + 20 4) 23x

leyla120209 @leyla120209

August 2022 1 2 Report

1) 3y-25-(11-5y)=17;
2) 5y-3-(3+4y)=8;
3) 23-(12x - 23) = 8x + 20
4) 23x - 45= 13x -(5x-6)
срочно надо

Answers & Comments

ыорп

Ответ:

$6\frac{5}{8}, 14, \frac{3}{20} , 3\frac{2}{5} .$

Пошаговое объяснение:

$3y-25-(11-5y)=17\\3y-25-11+5y=17\\3y+5y=17+25+11\\8y=53\\y=53:8\\y=6\frac{5}{8} .$ $5y-3-(3+4y)=8\\5y-3-3-4y=8\\5y-4y=8+3+3\\y=11+3\\y=14.$ $23-(12x-23)=8x+20\\23-12x+23=8x+20\\23-20=8x+12x\\3=20x\\x=\frac{3}{20} .$

$23x-45=13x-(5x-6)\\23x-45=13x-5x+6\\23x-13x+5x=6+45\\15x=51\\x=51:15\\x=3\frac{6}{15} \\x=3\frac{2}{5}$

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Answers & Comments

18 24 16

mn abcd ad23 mn 5

1 4 13 27 2800 10 25 1 2 25 25 25 25 15 443 1 3 16 16 16 18 36 36 36 24 4 2 4 6 1 3 5 1600 2600 10

vychislite srochno nado6b95235f70a3ae4f865cadd02a124471 5167

pri delenii naturalnogo chisla na 7 v ostatke ostaetsya 5 dokazhite chto pri dele

v ravnobedrennom treugolnike abc s osnovaniem as provedena mediana bd perimetr

motociklist proshel rasstoyanie ot punkta a do punkta b za 1 chas 10 minut na obra

reshite uravneniya 1 5x 4327 3x 213 2x 27 3x 3 32x 87 153 18x 4

predstav kvadrat dvuchlena v vide mnogochlena9453921daef43845a94f1b71b6c9bf53 62761

raskrojte skobki i privedite podobnye chleny 1 4a 3b 2s ab3c4a 2bc

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