Ответ:
1.б
2.а
3.а
4.в
5.а
6.в
7.
[tex] \frac{7x + 5}{1 - 3x} + \frac{4x + 6}{3x - 1} = \frac{ - (7x + 5) + 4x + 6}{3x - 1} = \frac{ - 7x - 5 + 4x + 6}{3x - 1} = \frac{ - 3 - 1}{3x + 1} = - 1[/tex]
8.
[tex] \frac{ {x}^{2} - 4x + 4 }{ {x}^{2} - 4 } = \frac{ {(x - 2)}^{2} }{(x - 2)(x + 2)} = \frac{x - 2}{x + 2} [/tex]
9.
[tex] \frac{x + 1}{2x + 4} + \frac{2}{ {x}^{2} - 4 } - \frac{x - 1}{2x - 4} = \frac{x + 1}{2(x + 2)} + \frac{2}{(x - 2)(x + 2)} - \frac{x - 1}{2(x - 2)} = \frac{ {x}^{2} + x - 2x - 2 + 4 - ( {x}^{2} - x + 2x - 2) }{2(x + 2) \times (x - 2)} = \frac{ {x}^{2} + x - 2x - 2 + 4 - {x}^{2} - x + 2 }{2(x + 2)(x - 2)} = \frac{ - 2(x - 2)}{2(x + 2) \times (x - 2)} = - \frac{1}{x + 2} [/tex]
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Answers & Comments
Ответ:
1.б
2.а
3.а
4.в
5.а
6.в
7.
[tex] \frac{7x + 5}{1 - 3x} + \frac{4x + 6}{3x - 1} = \frac{ - (7x + 5) + 4x + 6}{3x - 1} = \frac{ - 7x - 5 + 4x + 6}{3x - 1} = \frac{ - 3 - 1}{3x + 1} = - 1[/tex]
8.
[tex] \frac{ {x}^{2} - 4x + 4 }{ {x}^{2} - 4 } = \frac{ {(x - 2)}^{2} }{(x - 2)(x + 2)} = \frac{x - 2}{x + 2} [/tex]
9.
[tex] \frac{x + 1}{2x + 4} + \frac{2}{ {x}^{2} - 4 } - \frac{x - 1}{2x - 4} = \frac{x + 1}{2(x + 2)} + \frac{2}{(x - 2)(x + 2)} - \frac{x - 1}{2(x - 2)} = \frac{ {x}^{2} + x - 2x - 2 + 4 - ( {x}^{2} - x + 2x - 2) }{2(x + 2) \times (x - 2)} = \frac{ {x}^{2} + x - 2x - 2 + 4 - {x}^{2} - x + 2 }{2(x + 2)(x - 2)} = \frac{ - 2(x - 2)}{2(x + 2) \times (x - 2)} = - \frac{1}{x + 2} [/tex]