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AnnaAG
@AnnaAG
July 2022
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Помогите пожалуйста.
2x-1/2x+1 + 2x+1/1-2x = 8/1-4x2
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nKrynka
Решение
(2x-1)/(2x+0 + (2x+0/(1-2) = 8/(1-4x2)
ОДЗ: 1 - 4x^2
≠ 0
4x^2
≠ 1
x
≠ - 1/2; x ≠ 1/2
- (2x-1)*(2x-1) + (2x+1)*(2x+1)) - 8 = 0
-(4x^2 -4x +1) +(4x^2 + 4x + 1) - 8 = 0
-4x^2 + 4x - 1 + 4x^2 + 4x + 1 - 8 = 0
8x - 8 = 0
8x = 8
x = 1
Ответ: х = 1
3 votes
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Answers & Comments
(2x-1)/(2x+0 + (2x+0/(1-2) = 8/(1-4x2)
ОДЗ: 1 - 4x^2 ≠ 0
4x^2 ≠ 1
x ≠ - 1/2; x ≠ 1/2
- (2x-1)*(2x-1) + (2x+1)*(2x+1)) - 8 = 0
-(4x^2 -4x +1) +(4x^2 + 4x + 1) - 8 = 0
-4x^2 + 4x - 1 + 4x^2 + 4x + 1 - 8 = 0
8x - 8 = 0
8x = 8
x = 1
Ответ: х = 1