Ответ:
[tex]3-x^{2}[/tex]
Пошаговое объяснение:
[tex]\displaystyle 1)(x^{2} -1)(\frac{1}{x-1} -\frac{1}{x+1} -1)=[/tex]
[tex]\displaystyle=(x^{2} -1)(\frac{x+1}{(x-1)(x+1)} -\frac{x-1}{(x-1)(x+1)} -\frac{(x-1)(x+1)}{(x-1)(x+1)} )=[/tex]
[tex]\displaystyle=(x^{2} -1)(\frac{x+1-x+1-x^{2} +1}{(x-1)(x+1)} =(x^{2} -1)(\frac{3-x^{2} }{(x-1)(x+1)} )=\displaystyle[/tex]
[tex]\displaystyle=(x^{2} -1)*\frac{3-x^{2} }{x^{2} -1} =3-x^{2}[/tex]
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Answers & Comments
Ответ:
[tex]3-x^{2}[/tex]
Пошаговое объяснение:
[tex]\displaystyle 1)(x^{2} -1)(\frac{1}{x-1} -\frac{1}{x+1} -1)=[/tex]
[tex]\displaystyle=(x^{2} -1)(\frac{x+1}{(x-1)(x+1)} -\frac{x-1}{(x-1)(x+1)} -\frac{(x-1)(x+1)}{(x-1)(x+1)} )=[/tex]
[tex]\displaystyle=(x^{2} -1)(\frac{x+1-x+1-x^{2} +1}{(x-1)(x+1)} =(x^{2} -1)(\frac{3-x^{2} }{(x-1)(x+1)} )=\displaystyle[/tex]
[tex]\displaystyle=(x^{2} -1)*\frac{3-x^{2} }{x^{2} -1} =3-x^{2}[/tex]