Ответ:

1)

[tex] \sqrt{32} \times \sqrt{2} - \sqrt{32} \times \sqrt{5} - 3 \sqrt{10 } = 8 - 4 \sqrt{10 } - 3 \sqrt{10} = 8 - 7 \sqrt{10}[/tex]

a) (3⁴•2³/2¹•3⁴)+3²=4+9=13

b)

[tex]( {3}^{10} \times {3}^{ - 12} \div {3}^{ - 3}) + {8}^{0 } = {3}^{1} + 1 = 4[/tex]