1) а) 11 + 2х = 55 + 3х;
б) –15 – 3х = –7х + 45;
в) –3х – 17 = 8х – 105.
2) а) 2(2 + y) = 19 – 3y;
б) (4 – c) + 2(c – 3) = –13;
в) –3(3b + 1) – 12 = 12.
б) –15 – 3х = –7х + 45;
в) –3х – 17 = 8х – 105.
2) а) 2(2 + y) = 19 – 3y;
б) (4 – c) + 2(c – 3) = –13;
в) –3(3b + 1) – 12 = 12.
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Ответ:
Пошаговое объяснение:
а)11+2х=55+3х
2х-3х=55-11
-х=44
х=-44
б)-15-3х=-7х-45
-3х+7х=-45+15
4х=-30
х=-7,5
в)-3х-17=8х-105
-3х-8х=-105+17
-11х=-88
х=8
2.а) 2(2 + y) = 19 – 3y
4+2у=19-3у
2у+3у=19-4
5у=15
у=3
б) (4 – c) + 2(c – 3) = –13
4-с+2с-6=-13
-2+с=-13
с=-13+2
с=-11
в) –3(3b + 1) – 12 = 12
-9b-3-12=12
-9b-15=12
-9b=12+15
-9b=27
b=-3