а)
[tex]5(x-3)=4(x+2)\\5x-15=4x+8\\x=23[/tex]
б)
[tex]\displaystyle\\\frac{x+3}{6} =\frac{x-4}{7} \\7(x+3)=6(x-4)\\7x+21=6x-24\\x=-45[/tex]
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Answers & Comments
а)
[tex]5(x-3)=4(x+2)\\5x-15=4x+8\\x=23[/tex]
б)
[tex]\displaystyle\\\frac{x+3}{6} =\frac{x-4}{7} \\7(x+3)=6(x-4)\\7x+21=6x-24\\x=-45[/tex]