a) HBr → NaBr → Br₂ → HBr
1) HBr + NaOH = H₂O + NaBr
2) 2NaBr + Cl₂ = 2NaCl + Br₂
3) Br₂ + H₂ = 2HBr
б) HCl → Cl₂ → KClO → KCl → HCl → AgCl
1) 4HCl + MnO₂ = 2H₂O + Cl₂ + MnCl₂
2) Cl₂ + 2KOH = H₂O + KCl + KClO
3) 3KClO = 2KCl + KClO₃
4) KCl + HBr = HCl + KBr
5) HCl + AgBr = AgCl ↓ + HBr
в.1) NaBr → NaCl → Cl₂ → KClO₃ → KCl
1) NaBr + HCl = NaCl + HBr
2) 2NaCl = 2Na + Cl₂
3) 3Cl₂ + 6KOH = 3H₂O + 5KCl + KClO₃
4) 2KClO₃ = 3O₂ + KCl
в.2) NaBr → NaCl → Cl₂ → Ca(ClO)₂
3) 2Cl₂ + 2Ca(OH)₂ = 2H₂O + CaCl₂ + Ca(ClO)₂
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Verified answer
a) HBr → NaBr → Br₂ → HBr
1) HBr + NaOH = H₂O + NaBr
2) 2NaBr + Cl₂ = 2NaCl + Br₂
3) Br₂ + H₂ = 2HBr
б) HCl → Cl₂ → KClO → KCl → HCl → AgCl
1) 4HCl + MnO₂ = 2H₂O + Cl₂ + MnCl₂
2) Cl₂ + 2KOH = H₂O + KCl + KClO
3) 3KClO = 2KCl + KClO₃
4) KCl + HBr = HCl + KBr
5) HCl + AgBr = AgCl ↓ + HBr
в.1) NaBr → NaCl → Cl₂ → KClO₃ → KCl
1) NaBr + HCl = NaCl + HBr
2) 2NaCl = 2Na + Cl₂
3) 3Cl₂ + 6KOH = 3H₂O + 5KCl + KClO₃
4) 2KClO₃ = 3O₂ + KCl
в.2) NaBr → NaCl → Cl₂ → Ca(ClO)₂
1) NaBr + HCl = NaCl + HBr
2) 2NaCl = 2Na + Cl₂
3) 2Cl₂ + 2Ca(OH)₂ = 2H₂O + CaCl₂ + Ca(ClO)₂