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NirvanaRock
@NirvanaRock
October 2021
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1-cos2a+sin2a
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kirichekov
Verified answer
1-cos2α+sin2α
=(sin²α+cos²α)-(cos²α-sin²α)+2sinα*cosα=2sin²α+2sinα*cosα=
2sinα*(sinα+cosα)
3 votes
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NirvanaRock
Спасибо!
shevtsovavalia
1-cos2α+sin2α=sin²α+cos²α-(cos²α-sin²α)+2sinαcosα=
=2sin²α+2sinαcosα=2sinα(sinα+cosα)
1 votes
Thanks 0
NirvanaRock
Спасибо!
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Verified answer
1-cos2α+sin2α=(sin²α+cos²α)-(cos²α-sin²α)+2sinα*cosα=2sin²α+2sinα*cosα=2sinα*(sinα+cosα)=2sin²α+2sinαcosα=2sinα(sinα+cosα)