1) cos^4x=cos2x 2) 2sin^2x+cos4x=0. Created by 427v2. algebra-ru

1) cos^4x=cos2x 2) 2sin^2x+cos4x=0...

July 2022 1 10 Report

1) cos^4x=cos2x
2) 2sin^2x+cos4x=0

Answers & Comments

saratov12 Ответ. (sin(x))^4+(cos(x))^4=(cos(2*x))^2+1/4; (sin(x))^4+(cos(x))^4=((cos(x))^2-(sin(x))^2)^2+1/4; 0=-2*(cos(x))^2*(sin(x))^2+1/4; -0,5*(sin(2*x))^2+0,25=0; (sin(2*x))^2=0,5; sin(2*x1)=(0,5)^0,5; sin(2*x2)=-(0,5)^0,5;

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