(1-cosx)(4+3cos2x)=0
1-cosx=0
cosx=1
x=pi+2pin.
cos2x=-4/3
2x=+- (pi - arccos4/3) + 2pin
x=+-1/2pi- 1/2 arccos4/3 = pin
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Answers & Comments
1-cosx=0
cosx=1
x=pi+2pin.
cos2x=-4/3
2x=+- (pi - arccos4/3) + 2pin
x=+-1/2pi- 1/2 arccos4/3 = pin