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elena1lena
@elena1lena
August 2022
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1. дано 10 литров гидроксида натрия. сколько грамм осадка получится при взаимодействии с CuSO4? CuSO4+NaOH→Cu(OH)2↓+Na2SO4
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akulifeeva21
Дано: Решение:
V(NaOH)=10 л.
Vm=22,4 л\моль CuSO₄+2NaOH→Cu(OH)₂↓+Na₂SO₄
Найти: V(NaOH)=n*Vm
m(Cu(OH)₂)-? 10=22,4n
n=10\22,4=0,44 моль
(Cu(OH)₂=1\2n(NaOH)=1\2*0,44=0,22 моль
М(Cu(OH)₂=64+2+32=66+32=98 г\моль
m(Cu(OH)₂)=n*M=0,22*98=21,56 г.
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Answers & Comments
V(NaOH)=10 л.
Vm=22,4 л\моль CuSO₄+2NaOH→Cu(OH)₂↓+Na₂SO₄
Найти: V(NaOH)=n*Vm
m(Cu(OH)₂)-? 10=22,4n
n=10\22,4=0,44 моль
(Cu(OH)₂=1\2n(NaOH)=1\2*0,44=0,22 моль
М(Cu(OH)₂=64+2+32=66+32=98 г\моль
m(Cu(OH)₂)=n*M=0,22*98=21,56 г.