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huseynova1
@huseynova1
July 2022
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Найти производную у' если у=ln x/ √1-х^2
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Sergey2007789
у=ln х-1/х+1
y'=1/x+1/(x+1)^2=(x^2+3x+1)/x(x+1)
y'=1/x+1/x^2=x^2+x=(1+x)/x^2
y'=(2*sqrt(x^2+1)-2x(2x)*(1/2)/sqrt(x^2+1))/(x^2+1)=sqrt(x^2+1)/(x^2+1)^2
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Answers & Comments
у=ln х-1/х+1
y'=1/x+1/(x+1)^2=(x^2+3x+1)/x(x+1)
y'=1/x+1/x^2=x^2+x=(1+x)/x^2
y'=(2*sqrt(x^2+1)-2x(2x)*(1/2)/sqrt(x^2+1))/(x^2+1)=sqrt(x^2+1)/(x^2+1)^2