Ответ:
1. Mr(HCI)=1+35=36
2.Mr(Ca(OH)2)=40+(16+1)•2=74
3.Mr(FeSO4)=56+32+16•4=152
4.Mr(C6H12O6)=12•6+1•12+16•6=180
5.Mr(NH3)=14+1•3=17
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Ответ:
1. Mr(HCI)=1+35=36
2.Mr(Ca(OH)2)=40+(16+1)•2=74
3.Mr(FeSO4)=56+32+16•4=152
4.Mr(C6H12O6)=12•6+1•12+16•6=180
5.Mr(NH3)=14+1•3=17