Ответ:

Пошаговое объяснение:

1)  y=(8x-5)^17.

y'=((8x-5)^17)' = 17(8x-5)^16 * (8*x'-5') = 17*8(8x-5)^16 = 136(8x-5)^16.

2)  y=cos(x^4-15).

y' = (cos(x^4-15))' = -sin(x^4-15)*(x^4)'-15'} = -sin(x^4-15)(4x^3-0) =

= -4x^3sin(x^4-15).

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1)  y=(x^3+6x)^12  при x=0.

y'=((x^3+6x)^12)' = 12(x^3+6x)^11 * (x^3+6x)' = 12(x^3+6x)^11 *(3x^2+6*1)=

=12(x^3+6x)^11 *(3x^2+6).  =>  

при x=0 => y'= 12(0^3+6*0)^11*(3*0^2+6) = 12*0*(6) = 0.

2)  y=√(4x²-3)  при x=1.

y'=(4x²-3)^(1/2) = 1/2(1/√4x²-3) * (4x²-3)' =  1/2(1/√4x²-3) * (4*2*x-0) =

=4x/(√(4x²-3)).

при x=1 =>  y'=4*1/(√4*1²-3) = 4/1=4.