1. log_{5} (x+4)= 3log(5) 2+ log (5) 2. Created by MK20. algebra-ru

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1. log_{5} (x+4)= 3log(5) 2+ log (5) 2...

July 2022 1 19 Report

1. log_{5} (x+4)= 3log(5) 2+ log (5) 2

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МaргaритаД Дано:
$log5(x+4)=3log(5)2+log(5)2$

Решение:
$log5(x+4)=3log(5)2+log(5)2$
$ODZ=x+4>0$
$ODZ=x>-4$
$x+4=2^{3}*2$
$2^{3}*2=2^{3}*2^{1}=2^{3+1}=2^{4}=16$
$x+4=16$
$x=16-4$
$x=12$

Ответ:
$12$

1 votes Thanks 2

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