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Kseniy343
@Kseniy343
July 2022
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1. найдите наибольшее и наименьшее значение функции f(x)=x^3-3x^2+5 на отрезке [0;3]
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sedinalana
Verified answer
F`(x)=3x²-6x=3x(x-2)=0
x=0∈[0;3]
x=2∈[0;3]
f(0)=5 наиб
f(2)=8-12+5=1наим
f(3)=27-27+5=5 наиб
0 votes
Thanks 0
lexusenok
Verified answer
F'(x)=3x^2-6x=3x(x-2)
f'(x)=0
x=0
x=2
0<=x<=3
x=0
x=2
f(0)=5
f(2)=8-12+5=1
f(3)=27-27+5=5
На 0<=x<=3
fнаиб.=f(0)=f(3)=5
fнаим.=f(2)=1
1 votes
Thanks 0
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Answers & Comments
Verified answer
F`(x)=3x²-6x=3x(x-2)=0x=0∈[0;3]
x=2∈[0;3]
f(0)=5 наиб
f(2)=8-12+5=1наим
f(3)=27-27+5=5 наиб
Verified answer
F'(x)=3x^2-6x=3x(x-2)f'(x)=0
x=0
x=2
0<=x<=3
x=0
x=2
f(0)=5
f(2)=8-12+5=1
f(3)=27-27+5=5
На 0<=x<=3
fнаиб.=f(0)=f(3)=5
fнаим.=f(2)=1