Ответ:
Пошаговое объяснение:
y'= (ln(sin^2(5x + 7)))' u = sin (5x+7)
у'=(ln(sin^2(5x + 7)))'= (ln u²)'=2ln u*u'
у'=(2/sin(5x + 7))*5*2sin (5x+7) cos (5x+7)=20cos(5x+7)
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Ответ:
Пошаговое объяснение:
y'= (ln(sin^2(5x + 7)))' u = sin (5x+7)
у'=(ln(sin^2(5x + 7)))'= (ln u²)'=2ln u*u'
у'=(2/sin(5x + 7))*5*2sin (5x+7) cos (5x+7)=20cos(5x+7)